pOH = pKb+ log ([salt]/ [base]) byHenderson-Hasselbalch Equation pOH = 14- pH = 14 - 9.26 = 4.74 hence 4.74 = 4.74 + log ([salt]/ [base]) therefore log ([salt]/ [base]) = 0 so [salt]/ [base] = 1 since they have concentrationas 1M so the volume ratio is 1:1.