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Byju's Answer
Standard XII
Chemistry
Mole Concept
In which case...
Question
In which case is number of molecules of water maximum?
A
0.00224 L of water vapours at 1 atm and 273 K
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B
0.18 g of water
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C
18 mL of water
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D
10
–
3
mol of water
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Solution
The correct option is
C
18 mL of water
(1) moles of water =
0.00224
22.4
=
10
−
4
Molecules of water =
m
o
l
e
×
N
A
=
10
−
4
N
A
(2) Molecules of water =
m
o
l
e
×
N
A
=
0.18
18
N
A
=
10
−
2
N
A
(3) Mass of water =
18
×
1
= 18 g
Molecules of water =
m
o
l
e
×
N
A
=
18
18
N
A
=
N
A
(4) Molecules of water =
m
o
l
e
×
N
A
=
10
−
3
N
A
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