In which of the following, dissociation of $N{H}_{4}OH$ will be minimised

Q. Which of the following will form a buffer solution?
(a) $C{H}_{3}COONa+C{H}_{3}COOH$
(b) $NaCl+NaOH$
(c) $N{H}_{4}Cl+N{H}_{4}OH$
(d) $N{a}_{2}S{O}_4+H_{2}S{O}_4$

Q. In which of the following, dissociation of $N{H}_{4}OH$ will be minimised

Q. In the dissociation of $N{H}_{4}OH$, if $N{H}_{4}Cl$ is added what will be the change in $pH$ for the $N{H}_{4}OH$ solution ?

Q. ${\wedge }_m^{\circ }\left(N{H}_{4}OH\right)$ is equal to

Q. In the dissociation of $N{H}_{4}OH$,
$N{H}_{4}OH\left(aq\right)\rightleftharpoons N{H}_4^{+}\left(aq\right)+O{H}^{-}\left(aq\right)$
If $N{H}_{4}Cl$ is added to it, how will the $pH$ for the $N{H}_{4}OH$ solution change?