In which of the following molecules carbon atom marked with asterisk (*) is asymmetric?

(a) (i), (ii), (iii) and (iv) (b) (i) ,(ii) and (iii)

(c) (ii), (iii) and (iv) (d) (i), (iii) and (iv)

Open in App

Solution

The asymmetric/chiral carbon atom is that in which all of its four valencies with four different groups or atoms.

In molecules (i), (ii) and (iii), all have asymmetric carbon as each carbon has satisfied all four valencies with four different groups or atoms.

In compound (iv), carbon satisfies two of its valencies with two hydrogen atoms i.e., similar atom. No asterisk (*) will come for that carbon.

So, it is not an asymmetric carbon atom.

Hence, the correct option is (b). (i) ,(ii) and (iii)

Suggest Corrections

Similar questions

Q. Which of the following compounds are structural isomers of

C_{5} H_{10} O

?
(I) 2-methylbutanal
(II) Propyl ethanoate
(III) Pentanal
(IV) Pentanone

Arrange the following: $C H_{3} C H_{2} C H_{2} C l (I), C H_{3} C H_{2} C H C l C H_{3} (I I) {(C H_{3})}_{2} C H C H_{2} C l (I I I) a n d {(C H_{3})}_{3} C - C l (I V)$ in order of decreasing tendency towards $S N^{2}$ reaction

Q. Consider the following sets of quantum numbers:

	n	l	m	s
(i)	3	0	0	$+ \frac{1}{2}$
(ii)	2	2	1	$+ \frac{1}{2}$
(iii)	4	3	2	$- \frac{1}{2}$
(iv)	1	0	1	$+ \frac{1}{2}$

Which of the following sets of quantum number is not possible?

Q. Which of the following pair of compound will have the same order of rate of

S_{N} 1

and

S_{N} 2

Q. The decreasing order of acidic character of the following is:
I.

C H_{3} S H

II.

C H_{3} O H

III.

H_{2} O

IV. EtOH

Join BYJU'S Learning Program

In which of the following molecules carbon atom marked with asterisk (*) is asymmetric? (a) (i), (ii), (iii) and (iv) (b) (i) ,(ii) and (iii) (c) (ii), (iii) and (iv) (d) (i), (iii) and (iv)

In which of the following molecules carbon atom marked with asterisk (*) is asymmetric?

(a) (i), (ii), (iii) and (iv) (b) (i) ,(ii) and (iii)

(c) (ii), (iii) and (iv) (d) (i), (iii) and (iv)