In Young's double slit experiment, the two slits are illuminated by light of wavelength $5890\stackrel{\circ }{A}$ and the angular fringe width is ${0.2}^{\circ }$. If the whole apparatus is immersed in water, then the new angular fringe width will be (refractive index of water $=\frac{4}{3}$).

Q. In Young's double slit experiment, the two slits are illuminated by light of wavelength $5890\stackrel{\circ }{A}$ and the angular fringe width is ${0.2}^{\circ }$. If the whole apparatus is immersed in water, then the new angular fringe width will be (refractive index of water $=\frac{4}{3}$).

Q. In Young's double slit experiment the two slits are illuminated by light of wavelength 5890${}^{\circ }$A and the distance between the fringes obtained on the screen is 0.2${}^{\circ }$. If the whole apparatus is immersed in water then the angular fringe width will be (refractive index of water is 4/3):

Q. In young's double slit experiment the two slits are illuminated by light of wavelength $5890\dot{A}$ and it is observed that successive maxima or minima are seperated by angular displacement $2^{\circ }$. The whole apparatus is immersed in water, then find out angular fringe width is $({\mu }_w=\frac{4}{3})$.

Q. In a Young's double slit experiment,the fringe width is found to be $0.4mm$. What will be the new fringe width, if the whole apparatus is immersed in a water of refractive index 4/3 without disturbing the geometrical arrangement?

Q. In a Young's double slit experiment, the fringe width is found to be $0.4mm.$ If the whole apparatus is immersed in water of refractive index $\frac{4}{3}$ without disturbing the geometrical arrangement, the new fringe width will be