HM between the roots of the equation x2-10x+11 = 0 is
15
521
2120
115
Explanation for the correct option:
Let p and q be the roots of the equation x2-10x+11 = 0.
Now,
Sum of roots is
p+q = -ba = 10
Product of roots is
pq = ca = 11
∴HM of p, q = 2pq(p+q)
= 21110 = 2210 = 115
Hence option(D) is correct.
No. of real roots of the equation x3+x2 + 10x + sin x = 0, is :