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Reactivity Series

Iron can libe...

Question

Iron can liberate $H_{2}$ from dil. $H_{2} {S O}_{4}$ but copper cannot liberate $H_{2}$ from dil. $H_{2} {S O}_{4}$ .
Why?

A

Fe is more reactive than hydrogen.

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B

Fe is less reactive than hydrogen.

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C

Cu is less reactive than hydrogen.

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D

Cu is more reactive than hydrogen.

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Solution

The correct option is C Cu is less reactive than hydrogen.
Iron can liberate $H_{2}$ from dil. $H_{2} {S O}_{4}$ but copper cannot liberate $H_{2}$ from dil. $H_{2} {S O}_{4}$ . This happens because $F e$ is more reactive than hydrogen. It can thus displace hydrogen from sulphuric acid and form iron sulphate. Whereas copper is less reactive than hydrogen so, it cannot displace hydrogen from sulphuric acid.

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Similar questions

Q. Iron can liberate

H_{2}

H_{2} S O_{4}

but copper cannot liberate

H_{2}

H_{2} S O_{4}

Q. Iron can liberate

H_{2}

H_{2} {S O}_{4}

but copper cannot liberate

H_{2}

H_{2} {S O}_{4}

Q. On passing electricity through dil.

H_{2} {S O}_{4}

solution, the amount of substance liberated at the cathode and anode are in the ratio :

Z n

H_{2}

H C l

and also with dil

H_{2} {S O}_{4}

{N O}_{3}^{-}

ion is reduced in preference to hydronium ion.

Q. Which of the following produces colorless gas with dil.

H_{2} {S O}_{4}

?

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