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Question

Iron exhibits bcc structure at room temperature. Above 900°C, it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900°C (assuming molar mass and atomic radii of iron remains constant with temperature) is:

A
3 (3)4 (2)
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B
4 (3)3 (2)
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C
(3) (2)
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D
12
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Solution

The correct option is A 3 (3)4 (2)
For BCC, z = 2 and a = 4r (3)
For FCC, z = 4 and a = 2 2r
d25Cd900C=(ZMNAa3)BCC(ZMNAa3)FCC
=24(22r4r3)3
=(3342)

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