It is required to punch a hole of diameter $10mm$ on a sheet of thickness $3mm$. The shear strength of the work material is $420MPa$. The required punch force is

Q. In a sheet metal of $2$ mm thickness a hole of $10$ mm diameter needs to be punched. The yield strength in tension of the sheet material is $100$ MPa and its ultimate shear strength is $80$ MPa. The force required to punch the hole (in kN) is

Q. A hole of 50 mm diameter is to be punched on a 2 mm thick sheet. The shear stress for the material can be taken as 3.1 $kN/m{m}^2$. Assuming gradual variation of load with punch travel and penetration to thickness ratio = 0.5, the energy required to punch the hole is

Q. Determine the load required to punch a $20mm$ diameter hole in a $2mm$ thick sheet. The properties of the material of the sheet are:
Tensile strength $-580MPa$
Yield strength in tension $-410MPa$
Shear strength $-350MPa$
Yield strength in shear $-250MPa$
The load is $kN$ is

Q. We want to punch a hole of diameter 2 cm in a metal plate of thickness 8 mm. If shear strength of metal is $500\times {10}^{6}N/m^2$. What Force is required to punch hole?

Q. Circular blanks of $10$ mm diameter are punched from an aluminium sheet of $2$ mm thickness. The shear strength of aluminum is $80$ MPa. The minimum punching force required in kN is