1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VII
Mathematics
Dividing Terms with the Same Exponent
(x^mx^n)^m+n×...
Question
(
x
m
x
n
)
m
+
n
×
(
x
n
x
l
)
n
+
l
×
(
x
l
x
m
)
l
+
m
.
Open in App
Solution
(
x
m
x
n
)
m
+
n
×
(
x
n
x
l
)
n
+
l
×
(
x
l
x
m
)
l
+
m
[
x
m
x
n
=
x
m
−
n
]
[
(
x
)
m
−
n
]
m
+
n
×
[
(
x
)
n
−
l
]
n
+
l
×
[
(
x
)
l
−
m
]
l
+
m
[
x
m
×
x
n
=
x
m
+
n
]
&
[
(
a
+
b
)
(
a
−
b
)
=
a
2
+
b
2
]
x
m
2
−
n
2
×
x
n
2
−
l
2
×
x
l
2
−
m
2
x
m
2
−
n
2
+
n
2
−
l
2
+
l
2
−
m
2
x
o
=
1
.
Suggest Corrections
0
Similar questions
Q.
Prove that:
x
m
+
n
×
x
n
+
1
×
x
l
+
m
(
x
m
×
x
n
×
x
l
)
2
=
1
Q.
Prove that :
(i)
3
x
+
1
3
x
(
x
+
1
)
×
(
3
x
3
)
x
+
1
=
1
(ii)
(
x
m
x
m
)
m
+
n
⋅
(
x
n
x
l
)
n
+
l
⋅
(
x
l
x
m
)
l
+
m
=
1
Q.
(i) If
a
=
x
m
+
n
y
l
,
b
=
x
n
+
l
y
m
and
c
=
x
l
+
m
y
n
, prove that
a
m
-
n
b
n
-
l
c
l
-
m
=
1
.
(ii) If
x
=
a
m
+
n
,
y
=
a
n
+
l
and
z
=
a
l
+
m
, prove that
x
m
y
n
z
l
=
x
n
y
l
z
m
.
Q.
Solve:
(
x
m
x
−
n
)
m
−
n
×
(
x
n
x
−
l
)
n
−
l
×
(
x
l
x
−
m
)
l
−
m
Q.
If
a
=
x
m
+
n
.
y
l
;
b
=
x
n
+
l
.
y
m
and
c
=
x
l
+
m
.
y
n
prove that :
a
m
−
n
.
b
n
−
l
.
c
l
−
m
=
1
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Dividing Terms with the Same Exponent
MATHEMATICS
Watch in App
Explore more
Dividing Terms with the Same Exponent
Standard VII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app