Let A-x - x2-9 - 0- x - and B-x - -x-2- - 3- x - Then the number of elements in A - B is

A= { 3, 2, 1,0,1,2,3} B= {0,1,2,3,4} n(A)=7 ,n(B)=5, nbsp; n( A∩ B)=4 n( A Δ B) = nbsp; n(A B) + n(B A) = n(A) n( A∩ B) + n(B) n( A∩ B) =7 4+5 4 =12 8 =4 ...

You visited us 88 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Mathematics

Difference of Two Sets

Let A=x : x2-...

Question

Let $A = {x : x^{2} - 9 \leq 0, x \in Z}$ and $B = {x : | x - 2 | < 3, x \in Z} .$ Then the number of elements in $A Δ B$ is

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $4$
$A = {- 3, - 2, - 1, 0, 1, 2, 3}$
$B = {0, 1, 2, 3, 4}$

$n (A) = 7, n (B) = 5, n (A \cap B) = 4$
$n (A Δ B) = n (A - B) + n (B - A)$
$= n (A) - n (A \cap B) + n (B) - n (A \cap B)$
$= 7 - 4 + 5 - 4$
$= 12 - 8$
$= 4$

Suggest Corrections

Similar questions

Q. Let

A = {x : x^{2} - 9 \leq 0, x \in Z}

and

B = {x : | x - 2 | < 3, x \in Z} .

Then the number of elements in

A Δ B

Q. If

A = {x : x^{2} - 4 \leq 0, x \in Z}

and

B = {y : y^{2} - 9 \geq 0, y \in Z}

, then

n (A \cap B)

is equal to

Q. Let

f (x) = [x]

and

g (x) =

{\begin{matrix} 0, x \in Z x^{2}, x \in R - Z \end{matrix}

([.]

represents greatest integer function

) .

Then

Q. If

A = {x \in R : | x - 2 | > 1}, B = {x \in R : \sqrt{x^{2} - 3} > 1},

C = {x \in R : | x - 4 | \geq 2}

and

Z

is the set of all integers, then the number of subsets of the set

(A \cap B \cap C)^{c} \cap Z

Q. Let

Z

be the set of all integers.

A = {(x, y) \in Z \times Z : (x - 2)^{2} + y^{2} \leq 4}

B = {(x, y) \in Z \times Z : x^{2} + y^{2} \leq 4}

and

C = {(x, y) \in Z \times Z : (x - 2)^{2} + (y^{2} - 2)^{2} \leq 4}

If the total number of relations from

A \cap B

A \cap C

2^{p}

, then the value of

p

Join BYJU'S Learning Program

Let A={x:x2−9≤0,x∈Z} and B={x:|x−2|<3,x∈Z}. Then the number of elements in AΔB is

The correct option is B 4A={−3,−2,−1,0,1,2,3} B={0,1,2,3,4} n(A)=7,n(B)=5,n(A∩B)=4 n(AΔB)=n(A−B)+n(B−A) =n(A)−n(A∩B)+n(B)−n(A∩B) =7−4+5−4 =12−8 =4

Let $A = {x : x^{2} - 9 \leq 0, x \in Z}$ and $B = {x : | x - 2 | < 3, x \in Z} .$ Then the number of elements in $A Δ B$ is

The correct option is B $4$
$A = {- 3, - 2, - 1, 0, 1, 2, 3}$
$B = {0, 1, 2, 3, 4}$

$n (A) = 7, n (B) = 5, n (A \cap B) = 4$
$n (A Δ B) = n (A - B) + n (B - A)$
$= n (A) - n (A \cap B) + n (B) - n (A \cap B)$
$= 7 - 4 + 5 - 4$
$= 12 - 8$
$= 4$