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Question

Let α and β be two real numbers such that α+β=1 and αβ=1. Let Pn=(α)n+(β)n,Pn1=11 and Pn+1=29 for some integer n1. Then, the value of P2n is

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Solution

Given, α+β=1,ab=1
Quadratic equation with roots α,β is x2x1=0
α2=α+1
Multiflying both sides by αn1
αn+1=αn+αn1...(1)
Similarly,
βn+1=bn+bn1...(2)
Adding (1) & (2)
αn+1+βn+1=(αn+βn)+(αn1+βn1)
Pn+1=Pn+Pn1
29=Pn+11
Pn=18
P2n=182=324

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