Let f:{1,2,3}→{a,b,c} be one-one and onto function given by f(1)=a,f(2)=b and f(3)=c. Show that there exists a function g:{a,b,c}→{1,2,3} such that gof=Ix and fog=Ip where, X={1,2,3} and Y={a,b,c}.
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Solution
Given: f:(1,2,3)→(a,b,c) f(1)=a,f(2)=b and f(3)=c
Let: g:{a,b,c}→{1,2,3}
Such that g(a)=1,g(b)=2 and g(c)=3
Now gof, So, gof={(1,1),(2,2),(3,3)}=Ix= Identity function on set X={1,2,3}
Now, fog={(a,a),(b,b),(c,c)}=Iy= Identity function on set Y={a,b,c}