We have,
⎡⎢⎣1abω1cω2ω1⎤⎥⎦
Solving that,
=1−cω−a(ω−ω2c)
=1(1−cω)−aω(1−cω)
=(1−cω)(1−aω)
For non singular matrix.
c≠1ωanda≠1ω
⇒c≠ω2,a≠ω2
A and c must be ωand b can be ωorω2.
Then, total matrix =2.