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Question

Let y=f(x)=2x23x+2. The differential of y when x changes from 2 to 1.99 is

A
0.01
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B
0.18
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C
0.05
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D
0.07
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Solution

The correct option is C 0.05
δy=f(x).δx, changes from 2 to 1.99 δx=0.01δy=(4x3)δxδy=(4×23)(0.01)=0.05

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