Light is incident normally on face AB of a prism as shown in the figure A liquid of refractive index n is placed on face AC of the prism The prism is made of glass of refractive index 3/2 The limits of n for which total internal reflection takes place on face AC is

n > \frac{3 \sqrt{3}}{2}

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n > \sqrt{3}

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n < \frac{3 \sqrt{3}}{4}

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n < \frac{3 \sqrt{3}}{8}

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Solution

The correct option is C $n < \frac{3 \sqrt{3}}{4}$
Answer is C.

Please refer the below diagram.
Using Snell's Law:
$\frac{3 / 2}{n} = \frac{1}{sin 60}$ .
Therefore, $n = s i n 60 \times \frac{3}{2} = \frac{\sqrt{3}}{2} \times \frac{3}{2} = \frac{3 \sqrt{3}}{4}$ .Hence, the limit of n is lesser than $\frac{3 \sqrt{3}}{4}$

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Light is incident normally on face AB of a prism as shown in figure. A liquid of refractive index μ is placed on face AC of the prism. The prism is made of glass of refractive index 3/2. The limits of μ for which total internal reflection takes place on face AC is

Q. Light is incident normally on face AB of a prism as shown in figure. A liquid of refractive index

μ

is placed on the face AC of the prism. The prism is made of glass of refractive index 3/2. The limit of

μ

for which total internal reflection takes place on face AC is :

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Light is incident normally on face AB of a prism as shown in the figure A liquid of refractive index n is placed on face AC of the prism The prism is made of glass of refractive index 3/2 The limits of n for which total internal reflection takes place on face AC is

The correct option is C n<3√34Answer is C.Please refer the below diagram.Using Snell's Law:3/2n=1sin60.Therefore, n=sin60×32=√32×32=3√34.Hence, the limit of n is lesser than 3√34