Log-5-a-log-a x-2- then x is equal to 125-25-None of these-a-2-

The correct option is B 25 log_5 a. log_a x=2 ⇒ log_5 x=2 ⇒ x=5^2 = 25 Using log_b a. log_c b = log_c a ...

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Standard IX

Mathematics

Representation of Logarithmic Function

log_5 a.log_a...

Question

$l o g_{5} a . l o g_{a} x = 2$ , then $x$ is equal to

125

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$a^{2}$

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None of these

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Solution

The correct option is C
25

$l o g_{5} a . l o g_{a} x = 2 \Rightarrow l o g_{5} x = 2 \Rightarrow x = 5^{2} = 25$

Using $l o g_{b} a . l o g_{c} b = l o g_{c} a$

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log5 a.logax=2, then x is equal to

The correct option is C 25 log5 a.loga x=2⇒log5x=2⇒x=52=25 Using logb a.logc b=logc a

$l o g_{5} a . l o g_{a} x = 2$ , then $x$ is equal to

The correct option is C
25

$l o g_{5} a . l o g_{a} x = 2 \Rightarrow l o g_{5} x = 2 \Rightarrow x = 5^{2} = 25$

Using $l o g_{b} a . l o g_{c} b = l o g_{c} a$