Magnetite- - Fe-3O-4- can be converted into metallic ironftl heating with carbon monoxide as represented by this equation- Fe-3O-4 -4CO - 3Fe -4CO-2-How many kilogram of - Fe-3O-4- must be processed in this way to obtain 5 kg iron- if the process is 85

The correct option is D 8.12 kg #160;A balanced chemical equation can be given as: Fe_3O_4 +4CO → 3Fe +4CO_2 In the given equation:1 mol Fe_3O_4(232 ...

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Byju's Answer

Standard XII

Chemistry

Stoichiometric Calculations

Magnetite, ...

Question

Magnetite, $F e_{3} O_{4}$ , can be converted into metallic ironftl heating with carbon monoxide as represented by this equation
$F e_{3} O_{4} + 4 C O \to 3 F e + 4 C O_{2}$
How many kilogram of $F e_{3} O_{4}$ must be processed in this way to obtain 5 kg iron; if the process is 85% efficient ?
(Molar mass of $F e_{3} O_{4}$ is 232 g $m o l^{- 1}$ . )

6.92 kg

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8.12 kg

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20.8 kg

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24.4 kg

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Solution

The correct option is D 8.12 kg
A balanced chemical equation can be given as:
$F e_{3} O_{4} + 4 C O \to 3 F e + 4 C O_{2}$
In the given equation:

1 mol $F e_{3} O_{4} (232) = 3 m o l e F e (165 g)$

Amount of $F e_{3} O_{4}$ required for 5 kg iron $= \frac{232}{168} \times 5 k g$

Since, efficiency of the reaction is 85%, hence, We actual required amount of $F e_{3} O_{4}$ will be

$= \frac{100 \times 6.904}{85} k g$ , i.e., = 8.12 kg

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Similar questions

Q. Iron can be obtained by reduction of iron oxide

(F e_{3} O_{4})

with CO according to the reaction:

F e_{3} O_{4} + 4 C O \to 3 F e + 4 C O_{2}

How many kg of

F e_{3} O_{4}

should be heated with CO to get 3 kg of iron?

Q. Consider the following chemical reaction :

{F e}_{3} O_{4} + C O - F e + {C O}_{2} .

What mass of

{F e}_{3} O_{4}

is required to obtain

2 k g

of Fe if the process is

90 %

efficient?

Q. Calculate the mass of iron which will be converted into its oxide

(F e_{3} O_{4})

by the action of

8 g

of steam on it. [At mass of

F e = 56

]

F e + H_{2} O \to F e_{3} O_{4} + 4 H_{2}

Q. The equivalent mass of iron in the reaction,

3 F e + 2 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

would be:

Q. Calculate the weight of Iron which will be converted into its oxide by the action of 18 g of steam.
Given the reaction :

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

(Atomic mass of

F e = 56 g

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Magnetite, Fe3O4, can be converted into metallic ironftl heating with carbon monoxide as represented by this equationFe3O4+4CO→3Fe+4CO2How many kilogram of Fe3O4 must be processed in this way to obtain 5 kg iron; if the process is 85% efficient ?(Molar mass of Fe3O4 is 232 g mol−1. )