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Byju's Answer

Standard XII

Chemistry

Oxides of Group 16

Match list-I ...

Question

Match list-I with list-II:

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (i) 1

(b) $N_{2}$ (ii) 2

(c) $F_{2}$ (iii) 0

(d) $O_{2}$ (iv) 3

Choose the correct answer from the options given below

(a) - (i v); (b) - (i i i); (c) - (i i); (d) - (i)

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(a) - (i i); (b) - (i); (c) - (i v); (d) - (i i i)

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(a) - (i); (b) - (i i); (c) - (i i i); (d) - (i v)

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(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)

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Solution

The correct option is D $(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (iii) 0

(b) $N_{2}$ (iv) 3

(c) $F_{2}$ (i) 1

(d) $O_{2}$ (ii) 2

Hence, the correct option is (d).
$(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

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Similar questions

Q. Match List-I with List-II.

List-I	List-II
(Molecule)	(Bond order)
a. $N e_{2}$	i. 1
b. $N_{2}$	ii. 2
c. $F_{2}$	iii. 0
d. $O_{2}$	iv. 3

Choose the correct answer from the options given below:

Q. Match List I with List II and select the correct answer from the codes given below the lists.
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Q. Match List-I with List-II.

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Choose the correct answer from the options given below.

Q. Match List-I with List-II.

	List-I		List-II
	Electonic configuration of elements		$Δ_{1} H (i n k J m o l^{- 1})$
(a)	$1 s^{2} 2 s^{2}$	(i)	$801$
(b)	$1 s^{2} 2 s^{2} 2 p^{4}$	(ii)	$899$
(c)	$1 s^{2} 2 s^{2} 2 p^{3}$	(iii)	$1314$
(d)	$1 s^{2} 2 s^{2} 2 p^{1}$	(iv)	$1402$

Choose the most appropriate answer from the options given below:

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Match list-I with list-II:

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (i) 1

(b) $N_{2}$ (ii) 2

(c) $F_{2}$ (iii) 0

(d) $O_{2}$ (iv) 3

Choose the correct answer from the options given below

The correct option is D $(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (iii) 0

(b) $N_{2}$ (iv) 3

(c) $F_{2}$ (i) 1

(d) $O_{2}$ (ii) 2

Hence, the correct option is (d).
$(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

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List-I (Molecule)	List-II (Bond order)
(a) $N e_{2}$	(i) 1
(b) $N_{2}$	(ii) 2
(c) $F_{2}$	(iii) 0
(d) $O_{2}$	(iv) 3

Match list-I with list-II: List-I (Molecule) List-II (Bond order) (a)Ne2 (i) 1 (b)N2 (ii) 2 (c)F2 (iii) 0 (d)O2 (iv) 3 Choose the correct answer from the options given below

The correct option is D (a)−(iii);(b)−(iv);(c)−(i);(d)−(ii) List-I (Molecule) List-II (Bond order) (a)Ne2 (iii) 0 (b)N2 (iv) 3 (c)F2 (i) 1 (d)O2 (ii) 2 Hence, the correct option is (d). (a)−(iii);(b)−(iv);(c)−(i);(d)−(ii)

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Match list-I with list-II:

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (i) 1

(b) $N_{2}$ (ii) 2

(c) $F_{2}$ (iii) 0

(d) $O_{2}$ (iv) 3

Choose the correct answer from the options given below

The correct option is D $(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$

List-I
(Molecule) List-II
(Bond order)

(a) $N e_{2}$ (iii) 0

(b) $N_{2}$ (iv) 3

(c) $F_{2}$ (i) 1

(d) $O_{2}$ (ii) 2

Hence, the correct option is (d).
$(a) - (i i i); (b) - (i v); (c) - (i); (d) - (i i)$