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Question

Match List-I with List-II.
List-I
Reaction
List-II
Catalyst
(A) \(4NH_3(g) + 5O_2(g)\rightarrow 4NO(g) + 6H_2O(g)\) (I) \(NO(g)\)
(B) \(N_2(g) + 3H_2(g)\rightarrow 2NH_3(g)\) (II) \(H_2SO_4(l)\)
(C) \(C_{12}H_{22}O_{11}(aq) + H_2O(l) \rightarrow \underset{\text{Glucose}}{C_6H_{12}O_{6}}+ \underset{\text{Fructose}}{C_{6}H_{12}O_{6}} \) (III) \(Pt(s)\)
(D) \(2SO_2(g) + O_2(g)
\rightarrow 2SO_3(g)\)
(IV) \(Fe(s)\)

Choose the correct answer from the options given below:

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Solution

\((A) ~4NH_3(g) + 5O_2(g) \overset{Pt(s)}{\longrightarrow} 4NO(g) + 6H_2O(g)\)

\((B)~ N_2(g) + 3H_2(g) \overset{Fe(s)}{\longrightarrow} Fe(s) 2NH_3(g)\)

\((C)~C_{12}H_{22}O_{11}(aq) + H_2O(l)\overset{H_2SO_4(l)}{\longrightarrow} \underset{\text{Glucose}}{C_6H_{12}O_{6}}+ \underset{\text{Fructose}}{C_{6}H_{12}O_{6}} \)

\((D)~2SO_2(g) + O_2(g) \overset{NO(g)}{\longrightarrow}2SO_3\)

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