Match the following

1. $P C l_{3}$ (i). 2 lone pairs (I) 5 Ligands

2. $C l F_{3}$ (ii). 3 lone pair (II) 3 Ligands

3. $X e F_{6}$ (iii). 0 lone pair (III) 6 Ligands

4. $S b C l_{5}$ (iv). 1 lone pairs (IV) 4 Ligands

1 - (ii), (III); 2 - (ii), (II); 3 - (i), (I), 4 - (i), (I)

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1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I)

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1 - (ii), (II); 2 - (ii), (III); 3 - (ii), (II), 4 - (i), (I)

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1 - (iii), (II); 2 - (i), (III); 3 - (i), (II), 4 - (i), (II)

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Solution

The correct option is B
1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I)

Lets calculate the ep values first:

ep = $\frac{(V + L + A - C)}{2}$

(1) $P C l_{3} \Rightarrow \frac{(5 + 3)}{2} = 4 \Rightarrow$ 1 lone pair

(2) $C l F_{3} \Rightarrow \frac{(7 + 3)}{2} = 5 \Rightarrow$ 2 lone pair

(3) $X e F_{6} \Rightarrow \frac{(8 + 6)}{2} = 7 \Rightarrow$ 1 lone pair

(4) $S b C l_{5} \Rightarrow \frac{(5 + 5)}{2} = 5 \Rightarrow$ 0 lone pairs

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Match the following 1. PCl3 (i). 2 lone pairs (I) 5 Ligands 2. ClF3 (ii). 3 lone pair (II) 3 Ligands 3. XeF6 (iii). 0 lone pair (III) 6 Ligands 4. SbCl5 (iv). 1 lone pairs (IV) 4 Ligands

The correct option is B 1 - (iv), (II); 2 - (i), (II); 3 - (iv), (III), 4 - (iii), (I) Lets calculate the ep values first: ep = (V+L+A−C)2 (1) PCl3⇒(5+3)2=4⇒ 1 lone pair (2) ClF3⇒(7+3)2=5⇒ 2 lone pair (3) XeF6⇒(8+6)2=7⇒ 1 lone pair (4) SbCl5⇒(5+5)2=5⇒ 0 lone pairs

Match the following

1. $P C l_{3}$ (i). 2 lone pairs (I) 5 Ligands

2. $C l F_{3}$ (ii). 3 lone pair (II) 3 Ligands

3. $X e F_{6}$ (iii). 0 lone pair (III) 6 Ligands

4. $S b C l_{5}$ (iv). 1 lone pairs (IV) 4 Ligands