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Question

Mole fraction of ethanol in ethanol water mixture is 0.25. Hence,the percentage concentration of ethanol by weight of mixture is:

A
75%
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B
46%
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C
54%
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D
25%
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Solution

The correct option is B 46%
x2=n2n1+n2=0.25 (ethanol) (solute)(Mw2=46g)
x1=n1n1+n2=0.75 (water) (solvent)(Mw1=18g)
x1x2=n1n2=31W1×Mw2Mw1×W2=31
W1×4618×W2=3
W1W2=1.17
W1=1.17 W2
W2W1+W2=0.46.

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