Multiply the multiplicative inverse of $\frac{3}{5}$ and $\frac{4}{9}$ and add the additive inverse of $\frac{11}{4}$ to the product. Find the result.

The correct option is B 1
The multiplicative inverse of $\frac{3}{5}$ = $\frac{5}{3}$

The multiplicative inverse of $\frac{4}{9}$ = $\frac{9}{4}$

Their product $=\frac{5}{3}$$\times$$\frac{9}{4}$ =$\frac{15}{4}$

Additive inverse of $\frac{11}{4}$ = $\frac{-11}{4}$

$\Rightarrow \frac{15}{4}$ + $\frac{-11}{4}$ = $\frac{4}{4}$ = 1