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Standard VI

Mathematics

Relation between Different Units of Length

The distance ...

Question

The distance between Avinash’s home and his school is 4250 m. Express this distance in km.

3.25

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4.25

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5.25

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6.25

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Solution

The correct option is B 4.25
$D i s tan c e b e t w e e n A v i n a s h ’ s h o m e a n d h i s s c h o o l = 4250 m U sin g t h e f o l l o w i n g r e l a t i o n s; 1 k m = 1000 m O r 1 m = \frac{1}{1000} = 0.001 k m D i s tan c e b e t w e e n A v i n a s h ’ s h o m e a n d s c h o o l i n k m = 4250 \times 0.001 = 4.25 k m$

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The distance between Avinash’s home and his school is 4250 m. Express this distance in km.

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The distance between Avinash’s home and his school is 4250 m. Express this distance in km.

The correct option is B 4.25Distance between Avinash’s home and his school = 4250 m Using the following relations; 1 km = 1000 mOr 1 m= 11000 = 0.001 kmDistance between Avinash’s home and school in km = 4250 × 0.001= 4.25 km

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