Two balls are projected upward simultaneously with speeds $40\text{m/s}$ and $60\text{m/s}$. Relative position $\left(x\right)$ of second ball w.r.t. first ball at time $t=5\text{s}$ is :
[Neglect air resistance]

The correct option is D $100\text{m}$
Let the velocity of projections be $v_1$ and $v_2$.
Relative velocity of ball 2 w.r.t 1, $u_{rel}=v_2-v_1=60-40=20\text{m/s}$
Since, both the balls are moving under constant acceleration due to gravity. Therefore, relative acceleration of ball 2 w.r.t ball 1 will be zero.
$\Rightarrow a_{\text{rel}}=0$
Position of ball 2 w.r.t ball 1,
$s_{\text{rel}}=u_{\text{rel}}t+\frac{1}{2}{a}_{\text{rel}}{t}^2$
$\Rightarrow s_{\text{rel}}=20\times 5$
$\Rightarrow s_{\text{rel}}=100\text{m}$