In the diamond cubic structure, carbon atoms form an FCC while the other carbon atoms occupy alternate tetrahedral voids, the atoms being connected by covalent bonds. Then the packing efficiency is approximately

56%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

68%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

74%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

34%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 34%
$\frac{\sqrt{3} a}{4} = 2 R, R = \frac{\sqrt{3}}{8} a ∴ η = \frac{8 \times \frac{4}{3} π R^{3}}{a^{3}} \times 100 = \frac{8 \times \frac{4}{3} π 3 \sqrt{3}}{8^{3}} \times 100 = \frac{π \sqrt{3}}{16} \times 100 = 34 %$

Suggest Corrections

Similar questions

Q. Diamond has a three dimensional structure of

C

atoms formed by covalent bonds. The structure of diamond has face centred cubic lattice where

50 %

of the tetrahedral voids are also occupied by carbon atoms. The number of carbon atoms present per unit cell of diamond is____________

Q. In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is

356

pm, then the radius (in pm) of carbon atom is:

In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm, then radius of carbon atom is

Q. A crystalline solid is made of

X, Y

and

Z

elements. Atoms of

X

form fcc packing; atoms of

Y

occupy octahedral voids while atoms of

Z

occupy tetrahedral voids. What will be the simplest formula of solid is atoms along one body diagonal are removed.

Q. Each carbon atom is

s p^{3}

hybridized in diamond. The % of tetrahedral voids occupied in diamond is:

Join BYJU'S Learning Program

In the diamond cubic structure, carbon atoms form an FCC while the other carbon atoms occupy alternate tetrahedral voids, the atoms being connected by covalent bonds. Then the packing efficiency is approximately

The correct option is D 34%√3a4=2R,R=√38a∴ η=8×43πR3a3×100=8×43π3√383×100=π√316×100=34%

The correct option is D 34%
$\frac{\sqrt{3} a}{4} = 2 R, R = \frac{\sqrt{3}}{8} a ∴ η = \frac{8 \times \frac{4}{3} π R^{3}}{a^{3}} \times 100 = \frac{8 \times \frac{4}{3} π 3 \sqrt{3}}{8^{3}} \times 100 = \frac{π \sqrt{3}}{16} \times 100 = 34 %$