wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 5.0 m mol dm3 aqueous soluion of KCI has a conductance of 0.55 mS when when measued in a cell of cell constant 1.3 cm1. The molar conductivity of this solution in mSm2 mol1 is

(Round off to the Nearest Integer)

A
14
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
14.00
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
14.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

Conductance=ConductivityCell Constant

Conductivity=0.55×103×1.3 S cm1



Molar conductivity=Conductivity(S cm1)×1000Molarity(mol/L)

Molar conductivity=0.55×103×1.3×1005×103

Molar conductivity=143 S cm2mol1

Molar conductivity=14.3 mS m2 mol1

Molar conductivity14 mS m2 mol1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidation and Reduction_Tackle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon