$N a_{2} C O_{3} .10 H_{2} O$ , when exposed to air, looses water of crystallization and finally gives:

N a_{2} C O_{3} .4 H_{2} O

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N a_{2} C O_{3} . H_{2} O

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N a_{2} C O_{3} .7 H_{2} O

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N a_{2} C O_{3} .9 H_{2} O

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Solution

The correct option is B $N a_{2} C O_{3} . H_{2} O$
$N a_{2} C O_{3} .10 H_{2} O$ is efflorescent and looses 9 water molecules on exposure to air to give $N a_{2} C O_{3} . H_{2} O$ .

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