Name the product obtained in the following reaction- Pent - 1 - eneCH-3 - CH-2 - CH-2 - CH - CH-2H-2O-2- OH- 2-methyl butan - 2- ol- Pentan - 3 - ol- Pentan - 1 - ol- Pentan - 2 - ol-

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Nucleophilic Substitution Reaction

Name the prod...

Question

Name the product obtained in the following reaction?
$C H_{3} - C H_{2} - C H_{2} P e n t - 1 - e n e - C H = C H_{2} (B H_{3})_{2} - ----- \to H_{2} O_{2} / O H^{-}$ ?

P e n t a n - 1 - o l

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P e n t a n - 3 - o l

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P e n t a n - 2 - o l

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2 - m e t h y l b u t a n - 2 - o l

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Solution

The correct option is C $P e n t a n - 1 - o l$
Hydroboration-oxidation reaction at alkene gives alcohol by Anti-Markovnikoff's addition.
Thus $O H$ will go to less substituted $C$ of the alkene thus Pent-1-ene will give Pent-1-ol as:
$C H_{3} - C H_{2} - C H_{2} - C H = C H_{2} H_{2} O_{2} / H^{+} - ----- \to B_{2} H_{6} C H_{3} - C H_{2} - C H_{2} - C H_{2} C H_{2} O H$
option A is correct.

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Similar questions

Arrange the following compounds in increasing order of boiling point. Propan - 1 - ol, butan - 1 - ol, butan - 2 - ol, pentan - 1 - ol
(a) Propan-1-ol, butan-2-ol, butan - 1 - ol, pentan-1-o|
(b) Propan-1-ol, butan - 1 - ol, butan-2-ol, pentan-1-ol
(c) Propan-1-ol, butan-2-ol, butan-1-ol, pentan-1-ol
(d) Propan-1-ol, butan-1-ol, butan-2-ol, pentan-1-ol

Q. In which of the following reactions the inversion of configuration takes place?

(I)

p e n t a n - 2 - o l

S O C l_{2} \to

(II)

p e n t a n - 2 - o l

C O C l_{2} ⟶

(III)

p e n t a n - 2 - o l

(A) + S O C l_{2}

P y r i d i n e - ---- \to

(IV)

p e n t a n - 2 - o l

C O C l_{2}

P y r i d i n e - ---- \to

Q. Arrange the following compounds in the decreasing order of their boiling points
(i) Pentan -1- ol (ii) 2-methylbutan -2- ol (iii) 3- Methylbutan–2- ol.

Arrange the following sets of compounds in order of their increasing boiling points:

$A$ : Pentan-1-ol, butan-1-ol, butan-2-ol, ethanol, propan-1-ol, methanol

$B$ : Pentan-1-ol, n-butane, pentanal, ethoxyethane

C H_{3} - O H | C H - C H_{2} - C H_{3} A l_{2} O_{3} - -- \to 573 K C H_{3} - C H = C H - C H_{3}

Butane-2-ol But-2-ene

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Name the product obtained in the following reaction?CH3−CH2−CH2Pent−1−ene−CH=CH2(BH3)2−−−−−−→H2O2/OH−?

Name the product obtained in the following reaction?
$C H_{3} - C H_{2} - C H_{2} P e n t - 1 - e n e - C H = C H_{2} (B H_{3})_{2} - ----- \to H_{2} O_{2} / O H^{-}$ ?