Name two characteristics of the chemical reaction involving solutions of lead nitrate and potassium iodide.

1. When Lead nitrate($\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2$) reacts with Potassium iodide$\left(\mathrm{KI}\right)$, it gives lead iodide$\left({\mathrm{PbI}}_2\right)$ and potassium nitrate$\left({\mathrm{KNO}}_3\right)$ as the product.
2. Here, Lead iodide is the precipitate.
3. The reaction of Lead nitrate and Potassium iodide can be written as follows:

$$\begin{gathered} \mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)+2\mathrm{KI}\left(\mathrm{aq}\right)\to {\mathrm{PbI}}_2\downarrow +2{\mathrm{KNO}}_3\left(\mathrm{aq}\right) \\ (\mathrm{Lead}\mathrm{nitrate})(\mathrm{Potassium}\mathrm{iodide})(\mathrm{Lead}\mathrm{iodide})(\mathrm{Potassium}\mathrm{nitrate}) \end{gathered}$$

Characteristics:

1. A color change can be observed, where the Lead nitrate is white while the Lead iodide is yellow.
2. A precipitate is formed as a product. Lead iodide is a yellow-colored precipitate.