Naresh walked $2 k m 35 m$ in the morning and $1 k m 7 m$ in the evening. How much distance did he walk in all?

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Solution

We know that $1000 m = 1 k m$
$\Rightarrow 1 m = \frac{1}{1000} k m$
Now, lets convert the given units into $k m$

$2 k m 35 m = 2 k m + 35 m = 2 k m + (1 m \times 35) = 2 k m + \frac{1}{1000} k m \times 35 = 2 k m + 0.35 k m = 2.035 k m$

$1 k m 7 m = 1 k m + 7 m = 1 k m + 1 m \times 7 = 1 k m + \frac{1}{1000} k m \times 7 = 1 k m + 0.07 k m = 1.007 k m$

Distance travelled in morning $= 2 k m 35 m = 2.035 k m$
Distance travelled in evening $= 1 k m 7 m = 1.007 k m$
Ones $.$ Tenths Hundredths Thousandths
$2$ $.$ $0$ $3$ $5$
$1$ $.$ $0$ $0$ $7$
$3$ $.$ $0$ $4$ $2$
So, total distance travelled by Naresh
$= 2.035 + 1.007 = 3.042 k m$
Therefore, Naresh walked $3.042 k m$ in all.

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Addition of Decimals

Standard VI Mathematics

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Ones	$.$	Tenths	Hundredths	Thousandths
$2$	$.$	$0$	$3$	$5$
$1$	$.$	$0$	$0$	$7$
$3$	$.$	$0$	$4$	$2$