Nitration of benzene is carried out with conc. $HN{O}_3$ in presence of conc. $H_{2}S{O}_4$. The role of conc. $H_{2}S{O}_4$ is to provide :

The correct option is C electrophile during the reaction

Answer:- (C) electrophile during the reaction

Nitration in the benzene ring is an electrophilic substitution reaction, and the electrophile involved here is the nitronium ion, ${N{O}_2}^{+}$.

$H_{2}S{O}_4$ being a stronger acid than $HN{O}_3$ facilitates easy generation of ${N{O}_2}^{+}$ by protonating the latter.

$H_{2}S{O}_4+HN{O}_3⟶{N{O}_2}^{+}+{HS{O}_4}^{-}+H_{2}O$