Nitro glycerine is used as an explosive. The equation for the explosive reaction is
$4 C_{3} H_{5} (l) ((N O_{3}))_{3} \to 12 C O_{2} (g) + 10 H_{2} O (l) + 6 N_{2} (g) + O_{2} (g)$
(Atomic mass of $C = 12, H = 1, N = 14, O = 16)$
i) How many moles does the equation show for i) Nitroglycerine ii) gas molecules produced?
ii) How many moles of gas molecules are obtained from $1$ mole of nitroglycerine?
iii) What is the mass of $1$ mole of nitroglycerine?

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Solution

Given : $4 C_{3} H_{5} (l) ((N O_{3}))_{3} \to 12 C O_{2} (g) + 10 H_{2} O (l) + 6 N_{2} (g) + O_{2} (g)$
$i .$ The number of moles of nitroglycerine $= 4 m o l e s .$
The number of gas molecules $= 12 + 6 + 1 = 19 m o l e s$ .
$i i .$ $4$ moles of nitroglycerine gives $19$ moles of gas molecules.
Hence, $14$ mole of nitroglycerine gives $= \frac{14}{19} = 4.75$ moles of gas molecules.
$i i i .$ Mass of $1$ $m o l e o f$ C_3H_5{(NO_3)}_3\\ =36+5+186\\=227g$

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C = 12, O = 16, N = 14, H = 1, H e = 4

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N a = 23, C = 12, H = 1, O = 16)

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