Number of atoms present in 1.6 gm of methane are:

The correct option is C $3.01\times {10}^{23}$
No. of atoms in 1.6 gm of $C{H}_4=\frac{1.6}{16}\times N_A\times atomicity$
$=\frac{5\times N_A\times 1.6}{16}=\frac{5\times 6.02\times {10}^{23}\times 1.6}{16}=3.01\times {10}^{23}$