On electrolysis of dil. sulphuric acid using Platinum $\left(Pt\right)$ electrode, the product obtained at anode will be :

The correct option is D Oxygen gas
Dissociation of sulfuric acid,

$H_{2}S{O}_4\rightleftharpoons 2H^{+}\left(aq\right)+S{O}_4^{-2}\left(aq\right)$

Disssociation of water,

$H_{2}O\rightleftharpoons H^{+}\left(aq\right)+O{H}^{-}\left(aq\right)$

$\text{At Anode}:4O{H}^{-}\to 2H_{2}O\left(l\right)+O_2\left(g\right)+4e^{-}$

$\text{At cathode}:2H^{+}\left(aq\right)+2e^{-}\to H_2\left(g\right)$