One litre of $C O_{2}$ is passed through red-hot Coke. The volume becomes 1.4 litre at same temperature and pressure. The composition of the products is:

0.8 litre of

C O_{2}

and 0.6 litre of

C O

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0.7 litre of

C O_{2}

and 0.7 litre of

C O

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0.6 litre of

C O_{2}

and 0.8 litre of

C O

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0.4 litre of

C O_{2}

and 1.0 litre of

C O

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Solution

The correct option is A 0.8 litre of $C O_{2}$ and 0.6 litre of $C O$
$C O_{2} + C = 2 C O$

Let $x$ lit of $C O_{2}$ gives out $2 x$ lit of $C O$

Volume left of $C O_{2} = (1 - x)$

Total volume $= 1.4 l i t$

So, $(1 - x) + 2 x = 1.4$

$1 + x = 1.4$

$x = 1.4 - 1$

$= 0.4 l i t r e$

As $C O = 2 x$

$= 2 \times 0.4 = 0.8 l i t r e$

Volume of $C O_{2} = 1 - 4 - 0.8$

$= 0.6 l i t r e$

Hence, the correct option is $A$

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One litre of $C O_{2}$ is passed over hot coke, the volume becomes 1.4 litre. The composition of product is:

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