You visited us 22 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

One mole of ...

Question

One mole of $S O_{2} C l_{2}$ is dissolved in water and $C a (O H)_{2}$ is added to neutralise acidic solution. Number of moles of $C a (O H)_{2}$ required is :

Open in App

Solution

The balanced reactions are as follows:
$S O_{2} C l_{2} + 2 H_{2} O ⟶ H_{2} S O_{4} + 2 H C l$
$H_{2} S O_{4} + C a (O H)_{2} ⟶ C a S O_{4} + 2 H_{2} O$
$2 H C l + C a (O H)_{2} ⟶ C a C l_{2} + 2 H_{2} O$
Thus, total $C a (O H)_{2}$ required $= 2$ mol
Hence,2 moles of $C a (O H)_{2}$ required.

Suggest Corrections

Similar questions

S O_{2} C l_{2}

C a (O H)_{2}

C a (O H)_{2}

H C l (a q)

N a O H (a q)

C a (O H)_{2}

10

H C l (a q)

S O_{2} C l_{2}

N a O H

H^{+}

(S O_{2} C l_{2})

H_{2} S O_{4}

H C l

N a O H

1

S O_{2} C l_{2}

x

M n O_{4}^{-}

1

F e {(H C_{2} O_{4})}_{2}

y

C a {(O H)}_{2}

1

F e {(H C_{2} O_{4})}_{2}

x + y

Join BYJU'S Learning Program