Oxidation Number Of Pb In PbSO4

Explanation for Correct answer:-

Oxidation Number:

• The total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom is known as the Oxidation Number.
• Generally, the Oxidation number is the charge present on the ions.

Let the oxidation state of $\mathrm{Pb}$ in ${\mathrm{PbSO}}_4$ be x.

Also, the oxidation state of $\mathrm{Pb}$ and $\mathrm{O}$ is +6 and -2 respectively.

So,

Oxidation state of $\mathrm{Pb}$ + Oxidation state of $\mathrm{S}$ + 4 x Oxidation State of $\mathrm{O}$ = 0 (As the charge on ${\mathrm{PbSO}}_4$ is 0)

x + (+6) + 4(-2) = 0

x = +2

Therefore, the oxidation state of $\mathrm{Pb}$ in ${\mathrm{PbSO}}_4$ is +2.