Oxidation State Of S In H2SO3 Is________.

Oxidation Number:

• The total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom is known as the Oxidation Number.
• Generally, the Oxidation number is the charge present on the ions.

Let the oxidation number of $\mathrm{S}$ be x.

Also. we know the oxidation state of, $\mathrm{H}\mathrm{and}\mathrm{O}$ are +1, and -2 respectively.

For ${\mathrm{H}}_2{\mathrm{SO}}_3$ ,

2 x Oxidation state of $\mathrm{H}$ + Oxidation state of $\mathrm{S}$ + 3 x Oxidation state of $\mathrm{O}$ = 0 ( As the charge on ${\mathrm{H}}_2{\mathrm{SO}}_3$ is 0)

2(+1) + x + 3(-2) = 0

x = +4

Therefore, the oxidation state of $\mathrm{S}$ in ${\mathrm{H}}_2{\mathrm{SO}}_3$ is +4.