a body of mass 1.5kg is attached to a linear spring which vibrates in a frequency of 2.4hz. Calculate the spring constant of the system?

Q. A body of mass $1kg$ is made to oscillate on a spring of force constant $16N/m.$ Calculate:

Q. Two point masses of $3\text{kg}$ and $6\text{kg}$ are attached to opposite ends of a horizontal spring, whose spring constant is $300{\text{Nm}}^{-1}$, as shown in the figure. The natural vibration frequency of the system is, approximately,

Q. A $1kg$ block attached to a spring vibrates with a frequency of $1Hz$ on a frictionless horizontal table. Two springs identical to the original spring are attached in a parallel to an $8kg$ block placed on the same table. So, the frequency of vibration of the $8kg$ block is ;

Q. One end of a massless spring of natural length $50cm$ and spring constant $K$ is fixed on top of a frictionless inclined plane $\theta ={30}^{\circ }$ as shown. When a mass of $1.5kg$ is attached to the pre and it extends the spring by $2.5cm$ in equilibrium. The frequency of oscillations will be:

Q.

In the given figure, a body of mass $M$ is held between two massless spring on a smooth inclined plane. The free end of the spring are attached to firm supports. If each spring has spring constant $K$, the frequency of oscillation of the given body: