$P,Q$ and $R$ are three coplanar forces acting at a point and are in equilibrium. Given $P=1.9381kgwt.,\sin {\theta }_1=0.9659,$ the value of $R$ is (in $kgwt.)$

Q. P,Q and R are three co planar forces rating at a point and are in equilibrium:
Given $P=1.9318kgwt$ $sin=0.90591$, the value of $R$ ( in $kgwt$) is:

Q. Three forces P, Q & R are acting at a point in a plane. The angle between P and Q, Q and R are ${150}^o$ and ${120}^o$ respectively. Then for equilibrium, forces P, Q & R are in the ratio :

Q. The maximum and minimum resultant of two forces acting at a point are $29kgwt.$ and $5kgwt.$ respectively. If each force is increased by $3kgwt.$ then the magnitude of the resultant of new forces acting at right angles to each other is:

Q. Three forces $P,Q$ and $R$ are acting on a particle in the plane, the angle between $P$ and $Q$ and $Q$ and $R$ are ${150}^{\circ }$ and ${120}^{\circ }$ respectively. Then for equilibrium, forces $P,Q$ and $R$ are in the ratio

Q. Two forces acting on a particle in opposite directions have a resultant of 10 kg wt. If they act at right angles to each other, the resultant is 60kg wt. The forces are (in kg. wt):