Potassium sulphite on reacting with hydrochloric acid released _________ gas. $(C l_{2}, S O_{2}, H_{2} S)$ .

Open in App

Solution

Potassium sulphite on reacting with hydrochloric acid releases sulphur dioxide ( $S O_{2}$ ) gas.
$K_{2} S O_{3} + 2 H C l \to 2 K C l + H_{2} O + S O_{2}$

Suggest Corrections

Similar questions

Q. Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

Q. Identify the gas evolved when:
(i) Potassium sulphite is treated with dilute hydrochloric acid.

When sodium sulphite reacts with the dilute hydrochloric acid, salt X, water and gas Y is formed. Gas X decolourised pink potassium permanganate solution. Gas X is:

Q. Identify the gas evolved and give the chemical test in each of the following case :
(i) Dilute hydrochloric acid reacts with sodium sulphite.
(ii) Dilute hydrochloric acid reacts with iron (II) sulphide.

Which of the following gas is formed when potassium sulphite reacts with dilute nitric acid?

Join BYJU'S Learning Program

Potassium sulphite on reacting with hydrochloric acid released _________ gas. (Cl2,SO2,H2S).

Potassium sulphite on reacting with hydrochloric acid releases sulphur dioxide (SO2) gas.K2SO3+2HCl→2KCl+H2O+SO2

Potassium sulphite on reacting with hydrochloric acid released _________ gas. $(C l_{2}, S O_{2}, H_{2} S)$ .

Potassium sulphite on reacting with hydrochloric acid releases sulphur dioxide ( $S O_{2}$ ) gas.
$K_{2} S O_{3} + 2 H C l \to 2 K C l + H_{2} O + S O_{2}$