No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D The given reaction is a semi-pinacolone rearrangement.
Amine in presence of NaNO2+HCl will form diazonium salt. Then, the N2 (good leaving group) leaves to form a carbocation intermediate.
Then, rearrangement occurs to form a resonance stabilised oxonium ion.
Since, migratory of phenyl is higher than alkyl, 1, 2 - phenyl shift occurs to form the resonance stabilised carbocation.
Then, deprotonation occurs to give the final product.