Question 3 (i)
The relative humidity (in %) of a certain city for a month of 30 days was asfollows:
$\begin{matrix} 98.1 & 98.6 & 99.2 & 90.3 & 86.5 & 95.3 & 92.9 & 96.3 & 94.2 & 95.1 89.2 & 92.3 & 97.1 & 93.5 & 92.7 & 95.1 & 97.2 & 93.3 & 95.2 & 97.3 96.2 & 92.1 & 84.9 & 90.2 & 95.7 & 98.3 & 97.3 & 96.1 & 92.1 & 89 \end{matrix}$
(i) Construct a grouped frequency distribution table with classes
84 - 86, 86 - 88,etc.

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Solution

(i) A grouped frequency distribution table of class
Size 2 has to be constructed. The class intervals will be 84 − 86, 86−88, and 88 − 90…
By observing the data given above, the required table can be constructed as follows.
$\begin{matrix} Relative humidity(in %) & Number of days(frequency) 84 - 86 & 1 86 - 88 & 1 88 - 90 & 2 90 - 92 & 2 92 - 94 & 7 94 - 96 & 6 96 - 98 & 7 98 - 100 & 4 Total & 30 \end{matrix}$

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Similar questions

Q. The relative humidity (in %) of a certain city for a September month of

30

days was as follows:

$98.1$	$98.6$	$99.2$	$90.3$	$86.5$	$95.3$	$92.9$	$96.3$	$94.2$	$95.1$
$89.2$	$92.3$	$97.1$	$93.5$	$92.7$	$95.1$	$97.2$	$93.3$	$95.2$	$97.3$
$96.0$	$92.1$	$84.9$	$90.0$	$95.7$	$98.3$	$97.3$	$96.1$	$92.1$	$89$

Construct a grouped frequency distribution table with classes

84 - 86, 86 - 88

etc

Question 3 (i)
The relative humidity (in %) of a certain city for a month of 30 days was asfollows:
$\begin{matrix} 98.1 & 98.6 & 99.2 & 90.3 & 86.5 & 95.3 & 92.9 & 96.3 & 94.2 & 95.1 89.2 & 92.3 & 97.1 & 93.5 & 92.7 & 95.1 & 97.2 & 93.3 & 95.2 & 97.3 96.2 & 92.1 & 84.9 & 90.2 & 95.7 & 98.3 & 97.3 & 96.1 & 92.1 & 89 \end{matrix}$
(i) Construct a grouped frequency distribution table with classes
84 - 86, 86 - 88,etc.