Question 7

Ravi purchases 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.

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Solution

We know that 1000 g = 1 kg

$∴ 1 g = \frac{1}{1000} k g$

$5 k g 400 g = 5 k g + 400 g = 5 k g + 1 g \times 400 = 5 k g + \frac{1}{1000} k g \times 400 = 5.4 k g$

$2 k g 20 g = 2 k g + 20 g = 2 k g + 1 g \times 20 = 2 k g + \frac{1}{1000} k g \times 20 = 2.020 k g$

$10 k g 850 g = 10 k g + 850 g = 10 k g + 1 g \times 850 = 10 k g + \frac{1}{1000} k g \times 850 = 10.850 k g$

Weight of Rice = 5 kg 400 g = 5.400 kg
Weight of Sugar = 2 kg 20 g = 2.020 kg
Weight of Flour = 10 kg 850 g = 10.850 kg

$\begin{matrix} Hundreds & Tens & Ones & . & Tenths & Hundredths & Thousandths 0 & 0 & 5 & . & 4 & 0 & 0 0 & 0 & 2 & . & 0 & 2 & 0 0 & 1 & 0 & . & 8 & 5 & 0 + 0 & 1 & 8 & . & 2 & 7 & 0 & = 18.270 \end{matrix}$

Therefore, total weight of his purchases = 5.400 + 2.020 + 10.850 = 18.270 kg

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