Read the following carefully to mark the correct option out of the options given below:

Statement I: $S i - S i$ bond is weaker then $S i - O$ bond.
Statement II: Silicon forms double bonds with itself.

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

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Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.

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Statement I is true but Statement II is false.

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If Statement I and Statement II are both false.

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Solution

The correct option is C Statement I is true but Statement II is false.
Assertion is true but reason is false.Due to smaller size of oxygen atom, $S i - O$ bond is stronger than $S i - S i$ bond.

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Statement II Nuclides having odd number of protons and neutrons are generally unstable.

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Statement I: Boron always forms covalent bond

Statement II: The small size of $B^{3 +}$ favours formation of covalent bond

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Q. Read the following carefully to mark the correct option out of the options given below:

Statement I:

S i - S i

bond is weaker then

S i - O

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Statement II: Silicon forms double bonds with itself.

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Statement - II: Isoelectronic species should have same charges.

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Read the following carefully to mark the correct option out of the options given below: Statement I: Si−Si bond is weaker then Si−O bond. Statement II: Silicon forms double bonds with itself.

The correct option is C Statement I is true but Statement II is false.Assertion is true but reason is false.Due to smaller size of oxygen atom, Si−O bond is stronger than Si−Si bond.

Read the following carefully to mark the correct option out of the options given below:

Statement I: $S i - S i$ bond is weaker then $S i - O$ bond.
Statement II: Silicon forms double bonds with itself.

The correct option is C Statement I is true but Statement II is false.
Assertion is true but reason is false.Due to smaller size of oxygen atom, $S i - O$ bond is stronger than $S i - S i$ bond.