Resistors R-1- R-2 are connected in series- If the power dissipated by them is P-1- P-2 then nbsp-P1 nbsp- nbsp-P2 nbsp- nbsp-R1- nbsp-R2P1 nbsp- nbsp-P2 nbsp- nbsp-R2- nbsp-R1P1 nbsp- nbsp-P2 nbsp-1R1 nbsp- nbsp-1R2

The correct option is A P1 nbsp;: nbsp;P2 nbsp;= nbsp;R1: nbsp;R2In a series connection, the current flowing through the resistors is the same. If the ...

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Byju's Answer

Standard X

Physics

Electric Power

Resistors R_1...

Question

Resistors $R_{1}, R_{2}$ are connected in series. If the power dissipated by them is $P_{1}, P_{2}$ then

P_{1} : P_{2} = R_{1} : R_{2}

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P_{1} : P_{2} = R_{2} : R_{1}

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P_{1} : P_{2} = \frac{1}{R_{1}} : \frac{1}{R_{2}}

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Solution

The correct option is A $P_{1} : P_{2} = R_{1} : R_{2}$
In a series connection, the current flowing through the resistors is the same. If the current is taken as $I$ , then $P_{1} = I^{2} \times R_{1} a n d P_{2} = I^{2} \times R_{2}$
$H e n c e, P_{1} : P_{2} = R_{1} : R_{2}$ .

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