S1 : $\frac{1323}{1400}$ is a non terminating decimal.
S2 : A number $\frac{p}{q}$ where p and q are co-primes is terminating if q is of the form $2^n{.3}^m$ where n and m are non-negative integers.

S1 : Logarithm of a number x is defined for all negative values of x.
S2 : Logarithm of 1 to the base x (where x>1) = 0

If a terminating decimal can be expressed in the form $\frac{p}{q}$ where p and q are co-prime integers and q ≠ 0, and q is of the form $2^m{5}^n$ .where m and n are non-negative integers.

The solution for the equations $c_1$x + $b_1$y + $a_1$ = 0 and $c_2$x + $b_2$y + $a_2$ = 0 is

S1 :x = $\frac{(b_1{a}_2-b_2{a}_1)}{(c_1{b}_2-c_2{b}_1)}$

S2 : y =$\frac{(c_1{a}_2-c_2{a}_1)}{(a_1{b}_2-a_2{b}_1)}$

In the given figure, ABCD is a parallelogram and PD is parallel to QC.

S1 : $△$APD $\cong$ $△$BQC

S2 : area($△$APD) + area(PBCD) = area($△$BQC) + area(CDPB)