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Byju's Answer
Standard VII
Mathematics
Power of a Power
Simplify : ...
Question
Simplify :
128
−
2
7
−
(
625
−
3
)
−
1
4
+
14
(
2401
)
−
1
4
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Solution
128
−
2
7
−
625
−
3
×
−
1
4
+
14
(
2401
)
−
1
4
⟹
2
7
×
−
2
7
−
5
4
×
−
3
×
−
1
4
+
14
(
7
4
)
−
1
4
⟹
1
4
+
125
+
14
7
⟹
509
4
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Q.
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⎣
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⎤
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