Simplify
${64}^{-\frac{1}{3}}\times [{64}^{\frac{1}{3}}-{64}^{\frac{2}{3}}]$.

${64}^{-\frac{1}{3}}\times [{64}^{\frac{1}{3}}-{64}^{\frac{2}{3}}]$

$=(4^3{)}^{-\frac{1}{3}}\times \left[\right(4^3{)}^{\frac{1}{3}}-\left(4^3{)}^{\frac{2}{3}}\right]$

$=\frac{1}{4}.(4-4^2)$

$=\frac{1}{4}.(4-16)$

$=-3$